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The answer to this (and your other similar question) is most likely found in the somewhat unusual notation used for the system In ordinary terms, if you just take your system as a map between input and output signal, then you're absolutely right, it would not be time invariant3 Signals and Systems Part II Solutions to Recommended Problems S31 (a) xn= 8n 8 n 3 n 0 1 2 3 Figure S311 (b) xn = unun 5 0041T 0 1 2 3 4 5
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